32 .
A financier claims to be lending money at simple interest, But he includes the interest every six months for calculating the principal. If he is charging an interest of 10%, the effective rate of inte
34 .
A lent Rs. 5000 to B for 2 years and Rs 3000 to C for 4 years on simple interest at the same rate of interest and received Rs 2200 in all from both of them as interest. The rate of interest per annum
35 .
We have total amount Rs. 2379, now divide this amount in three parts so that their sum become equal after 2, 3 and 4 years respectively. If rate of interest is 5% per annum then first part will be ?
Lets assume that three parts are x, y and z. Simple Interest, R = 5% From question we can conclude that, x + interest (on x) for 2 years = y + interest (on y) for 3 years = z + interest (on y) for 4 years
(x+((x∗5∗2)/100))=(y+((y∗5∗3)/100))=(z+((z∗5∗4)/100)) (x+(x/10))=(y+(3y/20))=(z+(z/5)) =>11x/10=23y/20=6z/5 lets assume k = 11x/10=23y/20=6z/5 then x=10k/11 y=20k/23 z=5k/6 we know, x+y+z=2379 =>10k/11+20k/23+5k/6=2379 10k*23*6+20k*11*6+5k*11*23=2379*11*23*6 1380k+1320k+1265k=2379*11*23*6 3965k=2379*11*23*6 k=(2379∗11∗23∗6)/3965 by putting value of k we can get x x=10k/11 =>x=(10/11)∗((2379∗11∗23∗6)/3965) =>x=(10∗2379∗23∗6)/3965 =(2∗2379∗23∗6)/793 =2∗3∗23∗6=828